Determining the position of unknown element X in the Reactivity Series Essay Example for Free

Determining the position of unknown agent X in the Reactivity Series renderTo determine the position of division X in the responsiveness serial publicationHypothesisThe reactivity series is the arrangement of elements according to their reactivity. The most thermolabile element is placed at the precede and the least reactive at the bottom. The elements at the top can displace elements under them from their step upsIn the experiment, element X leave alone either have elements to a greater extent reactive or less reactive or both. Based on this, the position of the unknown element can be found out. Assuming that the element given is not super acid, and so potassium provide displace X from its compound thus we can say that potassium is to a greater extent reactive than X and X is below potassium in the reactivity series. Assuming that bullshit is less reactive than X X bequeath displace copper from its compound. This means that X is high than copper in the reactivity s eries than copper.In the experiment, the enthalpy (temperature) change will likewise fork over how reactive element X is. For example if X is right above Zinc in the reactivity series i.e. element X is aluminium, then the temperature difference among reacting Al with CuSO4 will be more than reacting Al with ZnSO4 or FeSO4. This is because as the distance ( keep down of elements in between between) the elements increases there is more difference in the reactivity level of the selected elements.When ?H (?Heat) is +ve, the reaction taking place is exothermic and when ?H is -ve, the reaction will be endothermic. When the recite of element between the elements reacting is more, then ?H of the reaction will also be more. For example if we take Zinc as element X, then Zinc is more reactive than steer but Zinc is even more reactive than Copper. This is because Copper is further below Lead in the reactivity series. Thus a reaction between Zinc and a Copper compound will be more reactive ( will have a higher ?H) than a reaction between Zinc and Lead.When ?E (?Energy) is +ve, the reaction taking place is endothermic and when ?E is -ve, the reaction will be exothermic. The reason behind the nature of ?H stated previously is the ?E (?Energy) of the reaction. Again more the number of elements between the reactants (according to the Reactivity Series) the lower the value of ?E i.e. more exothermic the reaction is. This is due to the causa of bonds present in various compounds. Taking the pervious example, a reaction between Zinc a Copper compound will give a lower ?E than a reaction between Zinc a Lead compound. Thus such reactions are more apparent.VariablesIndependentThe Metal abstruse utilise to react with Element XThe coat compound used to react with Element X was varied as this variation of the metal will help us determine the position of element X.DependentWhether a reaction takes place or notWhen contrary metal compounds are used, it is not necessary that a reaction takes place every time. The occurrence of a reaction depends on the metal present in the compound used.Energy Change (?E)?E depends on the compound used. In different compounds there are different types of bonds present and also every bond has a different nix level.Enthalpy Change (?H)?H depends on ?E. If ?E is -ve, then the reaction is exothermic if ?E is +ve, then the reaction will be endothermic.ControlledVolume of the Metal Compound takenThe volume of the metal compound taken must be kept constant as varying volumes can affect the last temperature.Size of Element X pillow slipThe size of the strip of Element X must also be kept constant as varying lengths can again affect the final temperature. mechanism1 Strip of Element X7 Test tubes5ml of CuSO45ml of FeSO45ml of MgSO45ml of PbNO35ml of KSO45ml of AgNO35ml of ZnSO4Procedure1. Take a strip of Element X and cut it into 7 equal pieces2. Pour 5ml of CuSO4 into a test tube3. mould a thermometer into one test CuSO4 an d measure the temperature4. Now put a piece of Element X into the test tube and measure ?H5. Repeat Steps 3 4 for FeSO4 MgSO4 PbNO3 KSO4 AgNO3 ZnSO4DiagramsResultsCompound reactionInitial Temperature (C)Final Temperature (C)?H (C)KSO4No21210MgSO4No21210ZnSO4No22220FeSO4No21210PbNO3Yes21222CuSO4Yes22253AgNO3Yes21265Graph interventionThe strip of element X given to us was shiny, this indicates that element X is not very reactive. thermolabile metals such as aluminium usually form a metal oxide layer on top of them thus losing their luster. When Element X was put in sulphate of potassium (which is a clear resultant role), the solution remained clear, and the piece of Element X also remained shiny thus indicating no reaction. Element X behaved as well for sulphates of Magnesium, Zinc Iron.A piece of Element X into PbNO3, after a lot of time, the solution started to incur cloudy (white precipitate), indicating a reaction. In this reaction the ?H was +1C.In CuSO4, the piece of Elem ent X was deposited with black precipitate all over. Also the solution becomes lighter blue as compared to the pure CuSO4(aq). It was a very slow process.In AgNO3, the solution turned cloudy (black) immediately after suspending the piece of Element X.If we observe the table below carefully, we notice that Element X did not react with K, Mg, Zn and Fe. exclusively it reacted with Pb, Cu Ag. This means that element X is Sn because the reactivity series goes as follows K, Na, Ca, Mg, Al, Zn, Fe, Sn, Pb, Cu, Ag, Au.Compound chemical EquationEnergy Equation?EKSO4(aq)MgSO4(aq)ZnSO4(aq)FeSO4(aq)Pb(NO3)2(aq)CuSO4(aq)AgNO3(aq)As I stated in my hypothesis, that the further aside the elements are (in the Reactivity Series) the lower the ?E is. This means that the reactions are more apparent (vigorous) and also more heat is produced in such reactions.ConclusionFrom this experiment, I reason that the Element X given to me is below Iron and above Lead in the reactivity series i.e. the element is Tin. I also intermit that the further apart the elements are (in the Reactivity Series) the higher the ?H and lower the ?E. I also conclude that such reactions are more reactive (apparent) as compared to those between element with a lower number of elements between them.EvaluationIn this experiment, if the mass of element X would have been measured and then used for reactions the reactions would have been more accurate and reliable.