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Tuesday 5 February 2013

Quadratic Equations

Week 3 Assignment
ZyAlicia Olvera
Mat 126
Instructor Laura Cella
Sep.10, 2012

office 1: Using the interesting method to act upon quadratic comparabilitys from India. personally I did not find this method any little confusing than the other methods I confuse learned about, I am not even sure I have a good understanding of this math, or quadratic equations.
A) x2-2x-13=0
hightail it the constant term to the right side of the equation:
x2-2x=13
figure severally term by four times the coefficient of x2
-42x=413 or 4x2-8x=52
Square the coefficient of the x term and add to twain sides of the equation:
4x2-8x+4=52+4 or 4x2-8x+4=56
bring in the material get-go of both sides:
(4x2-8x+4) = 56 or, (2x-2)2 = 56 or, 2x-2= 56 e.

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2x-2= +56
Set left side represent to validatory self-colored root of right side and solve for x:
x= (2+56)2 2x-2= -56
Set left side equal to negative square root of right side and solve for x:
So: x= (2+56)2 x=116 or x= (2-56)2 x=-108

C) x2 +12x-64= 0
give out the constant term to right side of equation
x2 +12x=64
Multiply each term by four times coefficient of x2
4x+ 4 12x= 4 64 or, 4x2+48x=256
Square the coefficient of x term and add to both sides of equation
4x2+48x+144=256+144 or, 4x2+48x+144=400
Take square root of both sides
4x2+48x+144 = 400 or, (2x+12)2 = 400 or, 2x+12= 20 or, 2x+12= +20
Set left side equal to positive square root of right side and solve for x
x= (-12+20)2= 4 2x+12= -20
Set left side equal to negative square root of right side and solve for x
x= (-12-20)2= -16
x=4 or x=-16

Part 2:
Try to find a number for x that when substituted in the formula yields a composite number.
x = 0
02-0+41=41
41 is a indigenous number

x = 2
22-2+41=
4-2+41=
2+41=43
43 is a prime number

x = 5
52-5+41=
25-5+41
20+41=61
61 is a prime number

x=6
62-6+41=
36-6+41=
30+41=71
71 is a prime number

x= 7
72-7+41=
49-7+41=
42+41=83
83 is a prime number

x=22
222-22+41=
484-22=462
462+41=503
503 is a prime number

x = 41
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